3(2x+1)^2+10=37

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Solution for 3(2x+1)^2+10=37 equation: 



3(2x+1)^2+10=37

We move all terms to the left:

3(2x+1)^2+10-(37)=0

We add all the numbers together, and all the variables

3(2x+1)^2-27=0

We move all terms containing x to the left, all other terms to the right

3(2x+1)^2=27

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